Explore the concepts of electron affinity, electronegativity, and ionization potential in chemistry. Learn about their definitions, trends across the periodic table, and the significance of these properties in understanding chemical behavior.
It is the energy required to remove the outermost (or highest energy) electron from a neutral atom in its gaseous state.
X(g)→X+(g)+ e −
Na(g) + Energy → Na+(g) + e– , H=+496 Kj/mol
Example
The ionization potential of lithium (Li), which is an alkali metal and is located in Group 1 of the periodic table.
The electron configuration of lithium is 1s² 2s¹.
The first ionization potential of lithium is the energy required to remove the outermost electron, which is in the 2s1 orbital.
The process can be represented as follows:
Li(g)→Li+(g)+e− 5.39 eV or 520 kJ/mol
The ionization energy for this process is approximately :5.39 eV or 520 kJ/mol
This means that it takes about 5.39 electron volts of energy to remove one mole of electrons from one mole of lithium atoms to produce one mole of lithium ions (Li+).
Ionization potential of Na
Ii depends on which electron is being removed.
Na(g)→Na+(g)+ e−
The ionization energy for this process is approximately :
5.14 eV or 49 kJ/mol
This means that it takes about 495 kJ/mol of energy to remove one mole of electrons from one mole of sodium atoms to produce one mole of sodium ions (Na+ ).
The relatively low first ionization potential of sodium is characteristic of alkali metals, which generally have low ionization energies due to their configuration with a single electron in their outermost shell.
For sodium (Na), the process of removing a second electron can be represented as follows:
Na+(g)→Na 2+(g)+ e −
The second ionization potential for sodium is higher than the first but lower than the third, as removing electrons becomes more difficult due to the increased positive charge on the ion.
Na2+(g)→Na 3+(g)+ e −
Generally, for alkali metals like sodium, the ionization potentials increase with each successive removal of electrons due to the increasing positive charge on the ion and the corresponding increase in the effective nuclear charge experienced by the remaining electrons.
Noble gases and alkali metals have distinct trends in their first ionization potentials due to their positions on the periodic table.
Noble Gases:
10Ne:[2He]:,2s2, 2p6
18Ar:[10Ne]:3s2,3p6
Alkali Metals:
11Na :[10Ne]:,3s1 19K:[18Ar],4s1
Why the first ionization potential of noble gases is very high?
Why the first ionization potential of alkali metals is lower than of all elements?
Large Atomic Size: Alkali metals have relatively large atomic sizes because they are located in the leftmost column of the periodic table. As you move down a group, the atomic size increases.
The valence electron in alkali metals is farther away from the nucleus.
In summary, the combination of a large atomic size and a single valence electron makes alkali metals more prone (tend) to losing that electron and having a lower first ionization potential compared to other elements.
The electron configuration of magnesium is : Mg:[10Ne]3s2
Here are the approximate values for the ionization potentials of magnesium:
First Ionization Potential: The energy required to remove the outermost (highest energy level) electron.
Mg(g)→Mg + (g)+e − First Ionization Potentia ∆H1=+737 kJ/mol
12Mg:1s2,2s2,2p6, 3s2 12Mg+:1s2,2s2,2p6, 3s1
Second Ionization Potential: The energy required to remove a second electron after the first one has already been removed.
Mg + (g)→Mg 2+ (g)+e − Second Ionization Potential ∆H1=+1450 kJ/mol
12Mg+:1s2,2s2,2p6, 3s1 12Mg++:1s2,2s2,2p6
Third Ionization Potential: The energy required to remove a third electron after the first two have already been removed.
Mg 2+(g) → Mg3+(g)+ e− ∆H1=+7730 kJ/mol
12Mg++:1s2,2s2,2p6 12Mg+++:1s2,2s2,2p5
Why the second ionization of Mg is higher than the first one?
Due to the increasing of the effective nuclear charge (Zeff)
The third ionization potential of magnesium is much higher than of its first and second ones because it results in the breaking up of a completely filled energy level
Why the first ionization potential of K is lower than that of Ca?
The first ionization potential of potassium (K) is lower than that of calcium (Ca) due to differences in their atomic structures and electron configurations.
Potassium (19K):1s2.2s2,2p6,3s2,3p6,4s1
K has one electron in its outermost energy level (valence electron).
The removal of this valence electron involves breaking it free from a relatively weak attraction compared to electrons in inner energy levels.
Calcium (20Ca): 1s2.2s2,2p6,3s2,3p6,4s2
Ca has two electrons in its outermost energy level.
The lower first ionization potential of potassium compared to calcium is primarily due to the fact that potassium has a single valence electron, and the removal of this electron requires less energy compared to the removal of an electron from the outermost shell of calcium, which has two electrons in that shell.
Why the second ionization potential of K is much higher than that of Ca?
Due to differences in their electron configurations and the removal of electrons from different energy levels.
Potassium (19K):1s2.2s2,2p6,3s2,3p6,4s1
The second ionization involves breaking up of a completely filled shell which requires more energy.
Calcium (Ca): Calcium (20Ca): 1s2.2s2,2p6,3s2,3p6,4s2
While Ca has low second ionization potential because, in the case of potassium, the second ionization involves removing an electron from 4s1
Ionization potential generally increases.
Ionization potential generally decreases.
Exceptions:
There can be occasional anomalies, especially when comparing elements in adjacent groups.
For example, elements in Group 15 (nitrogen, phosphorus, etc.) may not follow the expected trend due to the stability associated with half-filled and fully-filled orbitals.
The relation between the ionization potential and the atomic radius
The ionization potential and atomic radius have an inverse relationship in the periodic table.
As you move across a period from left to right or down a group from top to bottom, the ionization potential generally increases, while the atomic radius tends to decrease.
Across a Period (from left to right):
Ionization potential generally increases.
Atomic radius generally decreases.
Down a Group (from top to bottom):
Ionization potential generally decreases.
Atomic radius generally increases.
In summary, there is an inverse relationship between ionization potential and atomic radius: as the atomic radius increases, the ionization potential tends to decrease, and vice versa.
The ionization potential of P is higher than of S although P precedes sulphur in the P.T
Let’s compare sulfur (S) and phosphorus (P) in terms of electronic configuration and ionization potential:
Electronic Configuration:16S :1s2 2s2 2p6 3s2 3p4
Phosphorus (15P): 1s2 2s2 2p6 3s2 3p3
Because the atom becomes more stable when the 3p sublevel is half-filled with electrons as in phosphorous atom and removing an electron from it it will decrease its stability
The ionization potential of 13Al is lower than of Mg although Al comes next Mg in the same period
Because the atom becomes more stable when the 3s sublevel is completely filled with electrons as in magnesium atom and removing an electron from it will decrease its stability
Let’s compare aluminum (Al) and magnesium (Mg) in terms of electronic configuration and ionization potential:
Electronic Configuration:
Aluminum (13Al):1s2 2s2 2p6 3s2 3p1
Magnesium (12Mg): 1s2 2s2 2p6 3s2
ionization potential of sulphur and Aluminum Let’s compare sulfur (S) and aluminum (Al) specifically in terms of their first ionization potentials:
Sulfur (S):Atomic Number: 16
Electronic Configuration:1s2 2s2 2p6 3s2 3p4
Aluminum (Al):Atomic Number: 13
Electronic Configuration: 1s2 2s2 2p6 3s 2 3p 1
First Ionization Potential of Sulfur is higher than that of Al
Due to:
First Ionization Potential of Lithium is higher than that of Cs.Why?
The ionization potential generally decreases down a group in the periodic table, and cesium is located below lithium in Group 1.
Let’s compare lithium (Li) and cesium (Cs) specifically in terms of their first ionization potentials:
Lithium (3Li):Electronic Configuration:
1s2 2s1
Cesium (55Cs)::
1s22s22p63s23p64s23d104p65s24d105p66s1
Why does cesium have a lower first ionization potential than lithium?
X(g) + e − → X − (g)
Here are the general trends:
Across a Period (from left to right):Electron affinity tends to increase.
Due to :the increase of the atomic number leading to the decrease of atomic radius which makes it easier for nucleus to at attract a new electron.
As you move across a period from left to right, the atomic size generally decreases, and the effective nuclear charge increases.
Down a Group (from top to bottom):
Electron affinity tends to decrease.
Because: The increase in atomic number leading to the increase in The atomic size due to the addition of new electron shells and The ability of nucleus to accept an additional electron decreases
Why the electron affinity values for beryllium ,nitrogen and neon are close to zero ?
The electron affinity values for beryllium, nitrogen, and neon are close to zero that is for specific reasons related to their electronic configurations and atomic structures.
Beryllium (Be):1s2,2s2
Nitrogen(7N):1s2,2s2,2p3
Neon (10Ne):1s2,2s2,2p6
So the atom will be more stable when the sublevel :
2s is completely filled as in case of beryllium
2p is half-filled as in case of nitrogen atom
2p is completely-filled as in case of Ne atom
And the addition of an electron to any of them will decrease its stability
Why the electron affinity of chlorine (-348.6 KJ/mol ) is greater than that of fluorine (-348 KJ/mol) although chlorine comes next fluorine in the same group ?
Because fluorine atom is a smaller in size as it has smaller radius than chlorine atom so adding an electron suffer a strong repulsive force with the nine electron which decreases the released energy due to consuming a part of it to overcome the repulsive force
In summary, electronegativity is a concept related to chemical bonding, while electron affinity is more directly associated with the process of gaining an electron to form an ion.
How electronegativity changes across the periodic table:
Across a Period (from left to right):
Electronegativity increases from left to right due to:
The increase of atomic number leading to the decrease of atomic radius so the ability of atom to attract the electrons of the bond increase
Down a Group (from top to bottom):
Electronegativity decreases from top to bottom due to:
The increase in atomic number increases the atomic size due to the addition of new electron shells so the ability of atom to attract the electrons of bond decreases.
Notes:
-The Atoms of nonmetals group 7A (Halogens) are the greatest in the electronegativity while the atoms of the alkali metals of group 1A are the lowest in the electronegativity.
-Fluorine (F):is considered to be the most electronegative element while the cesium (Cs) is considered to be the lowest electronegative element .
Educational Websites:
Khan Academy (https://www.khanacademy.org/)
Chemguide (http://www.chemguide.co.uk/)
Online Databases:
PubChem (https://pubchem.ncbi.nlm.nih.gov/)
ChemSpider (http://www.chemspider.com/)